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Always include server response in Zotero.HTTP.request() errors

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This commit is contained in:
Dan Stillman 2017-04-07 22:34:19 -04:00
parent 3df66ccbe4
commit a64c6808e5
1 changed files with 2 additions and 4 deletions
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6
chrome/content/zotero/xpcom/http.js
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@ -252,10 +252,8 @@ Zotero.HTTP = new function() {
}
deferred.resolve(xmlhttp);
} else {
let msg = "HTTP " + method + " " + dispURL + " failed with status code " + xmlhttp.status;
if (xmlhttp.status == 400 || options.debug) {
msg += ":\n\n" + xmlhttp.responseText;
}
let msg = "HTTP " + method + " " + dispURL + " failed with status code " + xmlhttp.status
+ ":\n\n" + xmlhttp.responseText;
Zotero.debug(msg, 1);
deferred.reject(new Zotero.HTTP.UnexpectedStatusException(xmlhttp, msg));
}