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fix: Do not activate app when calling focus on inactive panel window (#40307)

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* fix: Do not activate app when calling focus on inactive panel window

* Use activate

* Use "activate" for all windows
This commit is contained in:
Felix Rieseberg 2023-11-06 13:38:12 -08:00 • committed by GitHub
parent 7999ea39e2
commit b55d7f4a16
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2 changed files with 48 additions and 1 deletions
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34
spec/api-browser-window-spec.ts
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@ -1196,6 +1196,40 @@ describe('BrowserWindow module', () => {
await isClosed3;
}
});
ifit(process.platform === 'darwin')('it does not activate the app if focusing an inactive panel', async () => {
// Show to focus app, then remove existing window
w.show();
w.destroy();
// We first need to resign app focus for this test to work
const isInactive = once(app, 'did-resign-active');
childProcess.execSync('osascript -e \'tell application "Finder" to activate\'');
await isInactive;
// Create new window
w = new BrowserWindow({
type: 'panel',
height: 200,
width: 200,
center: true,
show: false
});
const isShow = once(w, 'show');
const isFocus = once(w, 'focus');
w.showInactive();
w.focus();
await isShow;
await isFocus;
const getActiveAppOsa = 'tell application "System Events" to get the name of the first process whose frontmost is true';
const activeApp = childProcess.execSync(`osascript -e '${getActiveAppOsa}'`).toString().trim();
expect(activeApp).to.equal('Finder');
});
});
// TODO(RaisinTen): Make this work on Windows too.