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wimax/i2400m: SDIO specific TX queue's minimum buffer room for new message

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This patch specifies the TX queue's minimum buffer room required to
accommodate one smallest SDIO payload.
Please refer the documentation in the code.

Signed-off-by: Prasanna S. Panchamukhi <prasannax.s.panchamukhi@intel.com>
This commit is contained in:
Prasanna S. Panchamukhi 2010-04-13 16:36:26 -07:00 • committed by Inaky Perez-Gonzalez
commit 8a3a1b65ee
1 changed files with 7 additions and 0 deletions
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7
drivers/net/wimax/i2400m/sdio.c
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@ -483,6 +483,13 @@ int i2400ms_probe(struct sdio_func *func,
sdio_set_drvdata(func, i2400ms);
i2400m->bus_tx_block_size = I2400MS_BLK_SIZE;
/*
* Room required in the TX queue for SDIO message to accommodate
* a smallest payload while allocating header space is 224 bytes,
* which is the smallest message size(the block size 256 bytes)
* minus the smallest message header size(32 bytes).
*/
i2400m->bus_tx_room_min = I2400MS_BLK_SIZE - I2400M_PL_ALIGN * 2;
i2400m->bus_pl_size_max = I2400MS_PL_SIZE_MAX;
i2400m->bus_setup = i2400ms_bus_setup;
i2400m->bus_dev_start = i2400ms_bus_dev_start;