x86/fpu: Remove fpu_allocated()

It's an unnecessary obfuscation of a very simple allocation pattern.

Reviewed-by: Borislav Petkov <bp@alien8.de>
Cc: Andy Lutomirski <luto@amacapital.net>
Cc: Dave Hansen <dave.hansen@linux.intel.com>
Cc: Fenghua Yu <fenghua.yu@intel.com>
Cc: H. Peter Anvin <hpa@zytor.com>
Cc: Linus Torvalds <torvalds@linux-foundation.org>
Cc: Oleg Nesterov <oleg@redhat.com>
Cc: Peter Zijlstra <peterz@infradead.org>
Cc: Thomas Gleixner <tglx@linutronix.de>
Signed-off-by: Ingo Molnar <mingo@kernel.org>
This commit is contained in:
Ingo Molnar 2015-04-03 12:34:26 +02:00
commit 373244221a

View file

@ -569,14 +569,9 @@ static inline unsigned short get_fpu_mxcsr(struct task_struct *tsk)
}
}
static bool fpu_allocated(struct fpu *fpu)
{
return fpu->state != NULL;
}
static inline int fpu_alloc(struct fpu *fpu)
{
if (fpu_allocated(fpu))
if (fpu->state)
return 0;
fpu->state = kmem_cache_alloc(task_xstate_cachep, GFP_KERNEL);
if (!fpu->state)