x86/fpu: Remove fpu_allocated()
It's an unnecessary obfuscation of a very simple allocation pattern. Reviewed-by: Borislav Petkov <bp@alien8.de> Cc: Andy Lutomirski <luto@amacapital.net> Cc: Dave Hansen <dave.hansen@linux.intel.com> Cc: Fenghua Yu <fenghua.yu@intel.com> Cc: H. Peter Anvin <hpa@zytor.com> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Oleg Nesterov <oleg@redhat.com> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Signed-off-by: Ingo Molnar <mingo@kernel.org>
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1 changed files with 1 additions and 6 deletions
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@ -569,14 +569,9 @@ static inline unsigned short get_fpu_mxcsr(struct task_struct *tsk)
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}
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}
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static bool fpu_allocated(struct fpu *fpu)
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{
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return fpu->state != NULL;
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}
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static inline int fpu_alloc(struct fpu *fpu)
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{
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if (fpu_allocated(fpu))
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if (fpu->state)
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return 0;
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fpu->state = kmem_cache_alloc(task_xstate_cachep, GFP_KERNEL);
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if (!fpu->state)
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