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block: Simplify bsg complete all

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It took me a few tries to figure out what this code did; lets rewrite
it into a more regular form.

The thing that makes this one 'special' is the BSG_F_BLOCK flag, if
that is not set we're not supposed/allowed to block and should spin
wait for completion.

The (new) io_wait_event() will never see a false condition in case of
the spinning and we will therefore not block.

Cc: Linus Torvalds <torvalds@linux-foundation.org>
Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org>
Signed-off-by: Jens Axboe <axboe@fb.com>
This commit is contained in:
Peter Zijlstra 2015-02-03 12:55:31 +01:00 • committed by Jens Axboe
parent b7f120b211
commit 2c56124652
2 changed files with 40 additions and 47 deletions
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15
include/linux/wait.h
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@ -267,6 +267,21 @@ do { \
__wait_event(wq, condition); \
} while (0)
#define __io_wait_event(wq, condition) \
(void)___wait_event(wq, condition, TASK_UNINTERRUPTIBLE, 0, 0, \
io_schedule())
/*
* io_wait_event() -- like wait_event() but with io_schedule()
*/
#define io_wait_event(wq, condition) \
do { \
might_sleep(); \
if (condition) \
break; \
__io_wait_event(wq, condition); \
} while (0)
#define __wait_event_freezable(wq, condition) \
___wait_event(wq, condition, TASK_INTERRUPTIBLE, 0, 0, \
schedule(); try_to_freeze())