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											2008-05-19 16:53:02 -07:00
										 |  |  | /* | 
					
						
							| 
									
										
										
										
											2005-04-16 15:20:36 -07:00
										 |  |  |  * umul.S:      This routine was taken from glibc-1.09 and is covered | 
					
						
							|  |  |  |  *              by the GNU Library General Public License Version 2. | 
					
						
							|  |  |  |  */ | 
					
						
							|  |  |  | 
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							|  |  |  | 
 | 
					
						
							|  |  |  | /* | 
					
						
							|  |  |  |  * Unsigned multiply.  Returns %o0 * %o1 in %o1%o0 (i.e., %o1 holds the | 
					
						
							|  |  |  |  * upper 32 bits of the 64-bit product). | 
					
						
							|  |  |  |  * | 
					
						
							|  |  |  |  * This code optimizes short (less than 13-bit) multiplies.  Short | 
					
						
							|  |  |  |  * multiplies require 25 instruction cycles, and long ones require | 
					
						
							|  |  |  |  * 45 instruction cycles. | 
					
						
							|  |  |  |  * | 
					
						
							|  |  |  |  * On return, overflow has occurred (%o1 is not zero) if and only if | 
					
						
							|  |  |  |  * the Z condition code is clear, allowing, e.g., the following: | 
					
						
							|  |  |  |  * | 
					
						
							|  |  |  |  *	call	.umul | 
					
						
							|  |  |  |  *	nop | 
					
						
							|  |  |  |  *	bnz	overflow	(or tnz) | 
					
						
							|  |  |  |  */ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 	.globl .umul | 
					
						
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											2005-09-11 20:14:07 -07:00
										 |  |  | 	.globl _Umul
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											2005-04-16 15:20:36 -07:00
										 |  |  | .umul: | 
					
						
							| 
									
										
										
										
											2005-09-11 20:14:07 -07:00
										 |  |  | _Umul:	/* needed for export */ | 
					
						
							| 
									
										
										
										
											2005-04-16 15:20:36 -07:00
										 |  |  | 	or	%o0, %o1, %o4 | 
					
						
							|  |  |  | 	mov	%o0, %y		! multiplier -> Y | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 	andncc	%o4, 0xfff, %g0	! test bits 12..31 of *both* args | 
					
						
							|  |  |  | 	be	Lmul_shortway	! if zero, can do it the short way | 
					
						
							|  |  |  | 	 andcc	%g0, %g0, %o4	! zero the partial product and clear N and V | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 	/* | 
					
						
							|  |  |  | 	 * Long multiply.  32 steps, followed by a final shift step. | 
					
						
							|  |  |  | 	 */ | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 1 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 2 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 3 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 4 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 5 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 6 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 7 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 8 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 9 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 10 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 11 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 12 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 13 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 14 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 15 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 16 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 17 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 18 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 19 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 20 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 21 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 22 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 23 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 24 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 25 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 26 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 27 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 28 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 29 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 30 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 31 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 32 | 
					
						
							|  |  |  | 	mulscc	%o4, %g0, %o4	! final shift | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 	/* | 
					
						
							|  |  |  | 	 * Normally, with the shift-and-add approach, if both numbers are | 
					
						
							|  |  |  | 	 * positive you get the correct result.  With 32-bit two's-complement | 
					
						
							|  |  |  | 	 * numbers, -x is represented as | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 *		  x		    32 | 
					
						
							|  |  |  | 	 *	( 2  -  ------ ) mod 2  *  2 | 
					
						
							|  |  |  | 	 *		   32 | 
					
						
							|  |  |  | 	 *		  2 | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 * (the `mod 2' subtracts 1 from 1.bbbb).  To avoid lots of 2^32s, | 
					
						
							|  |  |  | 	 * we can treat this as if the radix point were just to the left | 
					
						
							|  |  |  | 	 * of the sign bit (multiply by 2^32), and get | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 *	-x  =  (2 - x) mod 2 | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 * Then, ignoring the `mod 2's for convenience: | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 *   x *  y	= xy | 
					
						
							|  |  |  | 	 *  -x *  y	= 2y - xy | 
					
						
							|  |  |  | 	 *   x * -y	= 2x - xy | 
					
						
							|  |  |  | 	 *  -x * -y	= 4 - 2x - 2y + xy | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 * For signed multiplies, we subtract (x << 32) from the partial | 
					
						
							|  |  |  | 	 * product to fix this problem for negative multipliers (see mul.s). | 
					
						
							|  |  |  | 	 * Because of the way the shift into the partial product is calculated | 
					
						
							|  |  |  | 	 * (N xor V), this term is automatically removed for the multiplicand, | 
					
						
							|  |  |  | 	 * so we don't have to adjust. | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 * But for unsigned multiplies, the high order bit wasn't a sign bit, | 
					
						
							|  |  |  | 	 * and the correction is wrong.  So for unsigned multiplies where the | 
					
						
							|  |  |  | 	 * high order bit is one, we end up with xy - (y << 32).  To fix it | 
					
						
							|  |  |  | 	 * we add y << 32. | 
					
						
							|  |  |  | 	 */ | 
					
						
							|  |  |  | #if 0 | 
					
						
							|  |  |  | 	tst	%o1 | 
					
						
							|  |  |  | 	bl,a	1f		! if %o1 < 0 (high order bit = 1), | 
					
						
							|  |  |  | 	 add	%o4, %o0, %o4	! %o4 += %o0 (add y to upper half) | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 1: | 
					
						
							|  |  |  | 	rd	%y, %o0		! get lower half of product | 
					
						
							|  |  |  | 	retl | 
					
						
							|  |  |  | 	 addcc	%o4, %g0, %o1	! put upper half in place and set Z for %o1==0 | 
					
						
							|  |  |  | #else | 
					
						
							|  |  |  | 	/* Faster code from tege@sics.se.  */ | 
					
						
							|  |  |  | 	sra	%o1, 31, %o2	! make mask from sign bit | 
					
						
							|  |  |  | 	and	%o0, %o2, %o2	! %o2 = 0 or %o0, depending on sign of %o1 | 
					
						
							|  |  |  | 	rd	%y, %o0		! get lower half of product | 
					
						
							|  |  |  | 	retl | 
					
						
							|  |  |  | 	 addcc	%o4, %o2, %o1	! add compensation and put upper half in place | 
					
						
							|  |  |  | #endif | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | Lmul_shortway: | 
					
						
							|  |  |  | 	/* | 
					
						
							|  |  |  | 	 * Short multiply.  12 steps, followed by a final shift step. | 
					
						
							|  |  |  | 	 * The resulting bits are off by 12 and (32-12) = 20 bit positions, | 
					
						
							|  |  |  | 	 * but there is no problem with %o0 being negative (unlike above), | 
					
						
							|  |  |  | 	 * and overflow is impossible (the answer is at most 24 bits long). | 
					
						
							|  |  |  | 	 */ | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 1 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 2 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 3 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 4 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 5 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 6 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 7 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 8 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 9 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 10 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 11 | 
					
						
							|  |  |  | 	mulscc	%o4, %o1, %o4	! 12 | 
					
						
							|  |  |  | 	mulscc	%o4, %g0, %o4	! final shift | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 	/* | 
					
						
							|  |  |  | 	 * %o4 has 20 of the bits that should be in the result; %y has
 | 
					
						
							|  |  |  | 	 * the bottom 12 (as %y's top 12).  That is: | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 *	  %o4		    %y | 
					
						
							|  |  |  | 	 * +----------------+----------------+ | 
					
						
							|  |  |  | 	 * | -12- |   -20-  | -12- |   -20-  | | 
					
						
							|  |  |  | 	 * +------(---------+------)---------+ | 
					
						
							|  |  |  | 	 *	   -----result----- | 
					
						
							|  |  |  | 	 * | 
					
						
							|  |  |  | 	 * The 12 bits of %o4 left of the `result' area are all zero;
 | 
					
						
							|  |  |  | 	 * in fact, all top 20 bits of %o4 are zero. | 
					
						
							|  |  |  | 	 */ | 
					
						
							|  |  |  | 
 | 
					
						
							|  |  |  | 	rd	%y, %o5 | 
					
						
							|  |  |  | 	sll	%o4, 12, %o0	! shift middle bits left 12 | 
					
						
							|  |  |  | 	srl	%o5, 20, %o5	! shift low bits right 20 | 
					
						
							|  |  |  | 	or	%o5, %o0, %o0 | 
					
						
							|  |  |  | 	retl | 
					
						
							|  |  |  | 	 addcc	%g0, %g0, %o1	! %o1 = zero, and set Z | 
					
						
							|  |  |  | 
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							|  |  |  | 	.globl	.umul_patch | 
					
						
							|  |  |  | .umul_patch: | 
					
						
							|  |  |  | 	umul	%o0, %o1, %o0 | 
					
						
							|  |  |  | 	retl | 
					
						
							|  |  |  | 	 rd	%y, %o1 | 
					
						
							|  |  |  | 	nop |